In this position White can't win by 1 P - B 5. Black's best answer would be P - Kt 3 draws. (The student should work this out.) He cannot win by 1 P - Kt 5, because P - Kt 3 draws. (This, because of the principle of the "

*opposition*"

{15}which governs this ending as well as all the Pawn-endings already given, and which will be explained more fully later on.)

White can win, however, by playing: 1 K - K 4, K - K 3. (If 1...P - Kt 3; 2 K - Q 4, K - K 3; 3 K - B 5, K - B 3; 4 K - Q 6, K - B 2; 5 P - Kt 5, K - Kt 2; 6 K - K 7, K - Kt 1; 7 K - B 6, K - R 2; 8 K - B 7 and White wins the Pawn.)

2 P - B 5 ch, K - B 3; 3 K - B 4, P - Kt 3. (If this Pawn is kept back we arrive at the ending shown in Example 7.) 4 P - Kt 5 ch, K - B 2; 5 P - B 6, K - K 3; 6 K - K 4, K - B 2; 7 K - K 5, K - B 1. White cannot force his Bishop's Pawn into Q (find out why), but by giving his Pawn up he can win the other Pawn and the game. Thus:

8 P - B 7, K × P; 9 K - Q 6, K - B 1; 10 K - K 6, K - Kt 2; 11 K - K 7, K - Kt 1; 12 K - B 6, K - R 2; 13 K - B 7, K - R 1; 14 K × P , K - Kt 1.

There is still some resistance in Black's position. In fact, the only way to win is the one given here, as will easily be seen by experiment.

15 K - R 6 (if K - B 6, K - R 2; and in order to win White must get back to the actual position, as against 16 P - Kt 6 ch, K - R 1 draws), K - R 1; 16 P - Kt 6, K - Kt 1; 17 P - Kt 7, K - B 2; 18 K - R 7, and White queens the Pawn and wins.

This ending, apparently so simple, should show the student the enormous difficulties to be surmounted, {16}even when there are hardly any pieces left, when playing against an adversary who knows how to use the resources at his disposal, and it should show the student, also, the necessity of paying strict attention to these elementary things which form the basis of true mastership in Chess.